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Find largest algorithm get a value for n, the size of the list get values for a1, a2, ... an, the list to be searched set the value of largest_so_far to a1 set the value of location to 1 set the value to i to 2 while ( i <= n ) do if a1 > largest_so_far then set largest_so_far to a1 set location to i add 1 to the value of i end of the loop print out the values of the largest_so_far and location stop question: if the numbers in our list were not unique and therefore the largest number could occur more than once, would the algorithm find the first occurrence? (select: true for "yes";false for "no")

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sqdancefan

Answer:

The algorithm as written here will do nothing useful, as a1 is always being compared to a1. It will only print a1 and location 1.

Step-by-step explanation:

As intended to be written, the comparison is "greater than", so there will only be a change in "largest_so_far" when a greater value is found. A value that is the same will not result in any new output. The algorithm as intended will find the first copy of the largest value.

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