Answer: Our required probability would be [tex]\dfrac{1}{4}[/tex]
Step-by-step explanation:
Since we have given that
Let A be the event that Kirk has the ace of spades.
Let B be the event that everyone has an ace.
So, P(A) Â = [tex]\dfrac{1}{52}[/tex]
P(B) = [tex]\dfrac{4}{52}[/tex]
And P(A∩B) = [tex]\dfrac{1}{52}[/tex]
So, P(Kirk has the ace of spades | each of them gets an ace)
[tex]\dfrac{P(A\cap B)}{P(B)}\\\\\\=\dfrac{\dfrac{1}{52}}{\dfrac{4}{52}}\\\\\\=\dfrac{1}{4}[/tex]
Hence, our required probability would be [tex]\dfrac{1}{4}[/tex]