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Find the equation (in slope-intercept form) of the line passing through the points with the given coordinates.
(1, -1), (2, -3)

Respuesta :

clemburg7
is parallel to the -axis. If the coordinates of the points and are (, 2) and (8, 6), respectively, find the value of .

gmany

Answer:

y = -2x + 1

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have two points (1, -1) and (2, -3).

Substitute:

[tex]m=\dfrac{-3-(-1)}{2-1}=\dfrac{-2}{1}=-2[/tex]

Put it and the coordinates of the point (1, -1) to the equation of a line:

[tex]-1=-2(1)+b[/tex]

[tex]-1=-2+b[/tex]          add 2 to both sides

[tex]1=b\to b=1[/tex]

Finally:

[tex]y=-2x+1[/tex]

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