Answer:
[tex]3.46[/tex] %
Explanation:
We have given cooler temperature that is [tex]T_c[/tex] = 6°C =273+6=279 K
And the warm temperature of water that is [tex]T_h=16^{\circ}C=16+273=289\ K[/tex]
The maximum possible efficiency is given by [tex]\eta =1-\frac{T_c}{T_h}[/tex]
So maximum efficiency [tex]\eta =1-\frac{T_c}{T_h}=1-\frac{279}{289}=0.0346=3.46[/tex] %