Answer: The required number is 91.
Step-by-step explanation: Given that a number has a tens digit that is 8 more than the ones digit. Zero is not one of the digits.
We are to find the number.
Let x and y represents the digit in ten's place and one's place respectively.
So, the number is [tex]n=10x+y.[/tex]
According to the given information, we have
[tex]x=8+y.[/tex]
Therefore,w e get
[tex]n=10x+y=10(8+y)+y=80+11y.[/tex]
Since the number is of two digits and x, y are not zero, so the required value of y is 1.
That is, given number is
[tex]n=80+11\times1=91.[/tex]
Thus, the required number is 91.
