Explanation:
It is given that,
Length of the string, l = 2 m
Mass of the string, [tex]m=5\ g=5\times 10^{-3}\ kg[/tex]
Hanged mass in the string, [tex]m'=200\ g=0.2\ kg[/tex]
1. The tension in the string is given by :
[tex]T=m'g[/tex]
[tex]T=0.2\times 9.8[/tex]
T = 1.96 N
2. Velocity of the transverse wave in the string is given by :
[tex]v=\sqrt{\dfrac{T}{M}}[/tex]
m = M/l
[tex]v=\sqrt{\dfrac{Tl}{m}}[/tex]
[tex]v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}[/tex]
v = 28 m/s
Hence, this is the required solution.
