Answer:
Value of Young's modulus is obtained as [tex]2.07\times 10^{11}N/m^{2}[/tex]
Explanation:
We know from the basic stress strain relationship
[tex]\sigma =E\times \epsilon[/tex]
Stress is obtained as
[tex]\sigma =\frac{P}{A}=\frac{5\times 10^{3}}{\frac{\pi\times D^{2}}{4}}=\frac{5\times 10^{3}}{0.25\times \pi \times (7.98\times 10^{-3})^{2}}=99.97MPa[/tex]
now the strain is obtained as
[tex]\epsilon =\frac{\Delta L}{L}=\frac{1.207\times 10^{-2}}{25}=4.828\times 10^{-4}[/tex]
using these values in the above equation we obtain E as
[tex]E=\frac{\sigma }{\epsilon }=\frac{99.97\times 10^{6}}{4.828\times 10^{-4}}=2.07\times 10^{11}N/m^{2}[/tex]
