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A beam of microwaves with λ = 0.9 mm is incident upon a 9 cm slit. At a distance of 1.5 m from the slit, what is the approximate width of the slit's image (cm)?

Respuesta :

Answer:

3 cm

Explanation:

According to the question,

[tex]D=1.5 m[/tex].

[tex]d=9 cm[/tex].

[tex]\lambda =0.9 mm[/tex].

Now the approximate slit's image width is equal to width of central maxima.

And width of central maxima is twice the width from center to first maxima

So,

[tex]y=2\frac{\lambda (D)}{d}[/tex].

Substitute all the variable in above equation.

[tex]y=\frac{(2)0.9\times 10^{-2} m(1.5 m) }{0.09 m}[/tex].

[tex]y=3 cm[/tex].

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