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If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) Calculate the minimum speed, in meters per second, required to take a 84 m radius curve banked at 16° so that you don't slide inwards, assuming there is no friction. (b) What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 16 km/h?

Respuesta :

Answer:

minimum speed is 15.35 m/s

frictional coefficient  is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and   minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² =  236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 =  0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245  = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient  is 0.26

onyebuchinnaji

The minimum speed needed to drive along the road without sliding inward is 15.36 m/s.

The minimum coefficient of friction needed for a frightened driver to take the same curve is 0.024.

The given parameters;

  • radius of the curve, r = 84 m
  • banking angle, θ = 16⁰

The minimum speed needed to drive along the road without sliding inward is calculated as follows;

[tex]v_{min} = \sqrt{rg \times tan(\theta)} \\\\v_{min} = \sqrt{84\times 9.8 \times tan(16)}\\\\v_{min} = 15.36 \ m/s[/tex]

The minimum coefficient of friction needed

speed of the car, v = 16 km/h = 4.44 m/s

[tex]\mu F_n = F_c \\\\\mu mg = \frac{mv^2}{r} \\\\\mu = \frac{v^2}{rg}\\\\\mu = \frac{(4.44)^2}{(84\times 9.8)} \\\\\mu = 0.024[/tex]

Learn more here:https://brainly.com/question/15415163

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