Answer:
Step-by-step explanation:
Given that recent study conducted by the government attempts to determine proportion of people who support further increase in cigarette taxes.
Sample size = n =2500
Sample persons favouring =1900
Population proportion = 78%
Population std deviation = [tex]\sqrt{\frac{pq}{n} } =\sqrt{\frac{0.78*0.22}{2500} } \\=0.00828[/tex]
[tex]H_0: p = 0.78\\H_a: p \neq 0.78[/tex]
(Two tailed test)
Sample proportion = [tex]\frac{1900}{2500} =0.76[/tex]
p difference = -0.02
Test statsitic z = p diff / std dev of p
= [tex]\frac{-0.02}{0.00828} \\=-2.415[/tex]
Since this lies outside 95% of (-1.96, 1.96) we reject H0.
The provided data reveals that the proportion of all citizens are in favor of increasing the tax on cigarette cannot be taken as 78%.