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A game of mistle consists of 5 teams; 4 teams lose and 1 team wins. Twenty-nine teams enter a mistle tournament. For each round of competition, games are played with 5 teams and any team who can not be assigned to a game gets a “bye” to the next round. How many games must be played to determine the tournament champion

Respuesta :

Answer:

8 games

Step-by-step explanation:

Total teams = 29

A game of mistle consists of 5 teams; 4 teams lose and 1 team wins

When first round is played within 5 teams

So, remaining teams= 29-5 = 24

Now 1 team wins in the first round

So, now the remaining teams become 24+1= 25

So, in every game we loose 4 teams

So, If form AP : 29,25,........,1

A = first term = 29

d = common difference = -4

Formula of nth term = [tex]a_n=a+(n-1)d[/tex]

[tex]1=29+(n-1)(-4)[/tex]

[tex]\frac{-28}{-4}=n-1[/tex]

[tex]7=n-1[/tex]

[tex]8=n[/tex]

Hence 8 games must be played to determine the tournament champion

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