A manufacturer of rechargeable laptop batteries markets its batteries as having, on
average, 500 charges. A consumer group decides to test this claim by assessing the
number of times 30 of their laptop batteries can be recharged and finds the average is 497, with a standard deviation of 10.The resulting p-value is .1111; thus, the null hypothesis is not rejected. The consumer group concludes that the manufacturer.

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JeanaShupp JeanaShupp · Answer 1 · 2019-08-28T07:54:55+02:00

Let [tex]\mu[/tex] be the population mean.

By considering the given information , we have

[tex]H_0:\mu=500\\\\H_a:\mu\neq500[/tex], since the alternative hypothesis is two tailed , so the test is two tail test.

Given : Sample size : n=30

Sample mean : [tex]\overline{x}=497[/tex]

Then, Standard deviation : [tex]\sigma=10[/tex]

The p-value = 0.1111, the null hypothesis is not rejected.

Thus , we conclude that we have evidence to accept the company's claim that the batteries have on average 500 charges.