The image of a plant is 4.0 cm from a concave spherical mirror having a radius of curvature of 10 cm. Where is the plant relative to the mirror?

Respuesta :

Answer:

The plant is placed at 2.22 cm on left hand side of the mirror.

Explanation:

Distance of the object from the mirror = u

Distance of an image from the mirror = v = 4.0 cm

Radius of the Curvature of the mirror ,r= 10 cm

[tex]f=\frac{-r}{2}[/tex]

[tex]f=\frac{-10 cm}{2}= -5 cm[/tex]

1 ) v = +4.0 cm (Image is on the other side)

[tex]\frac{1}{-5 cm}=\frac{1}{u}+\frac{1}{4.0 cm}[/tex]

u = -2.22 cm

2) v = -4.0 cm (Image is on the same side)

[tex]\frac{1}{-5 cm}=\frac{1}{u}+\frac{1}{-4.0 cm}[/tex]

u = 20 cm (not possible)

So, the distance of plant from the mirror is 2.22 cm