Respuesta :
Answer:
a)Li (liquid)
b) CH₃OCH₃ (liquid)
c) Xe (gas)
d) CO₂ (gas)
e) O₃ (gas)
f)N₂O₄ (gas)
Explanation:
Entropy is the measure of the degree of randomness in a thermodynamic system.
The entropy of gases is more than liquids and the entropy of liquids are more than solids. This is because gases are weakly held and posses higher degree of randomness and solids are mostly ordered.
a)Li (liquid)
Liquids are less ordered than solids, therefore greater entropy
b) CH₃OCH₃ (liquid)
It has weaker intermolecular forces, so molecules are in less fixed position when compared to C₂H₅OH (liquid) which posses hydrogen bonding. So, CH₃OCH₃ has greater entropy
c) Xe (gas)
It has greater value of molar mass than Ar (g), therefore Xe (g) has greater entropy .
d) CO₂ (gas)
It has greater molar mass than CO (gas); therefore CO₂ (gas) has greater entropy.
e) O₃ (gas)
It not only does O₃ have a greater molar mass than O₂ (gas) but also, it is more complex that O₂ which means that it can exhibit more vibrational motion; therefore O₃ (g) has greater entropy.
f)N₂O₄ (gas)
It has greater molar mass than NO₂(g) ; therefore N₂O₄(g) has greater entropy.
The given compounds with greater entropy include; Li(l) , CH3OCH3(l), Xe(g), CO2(g), O3(g), and N2O4(g)
What is standard entropy?
Standard entropy is the entropy of one mole of pure substance at a standard pressure and temperature.
Entropy measures the degree of randomness in a thermodynamic system.
Entropy of gases > entropy of liquids > entropy of solids.
Given compounds
- (a) Li (liquid) > Li (solid)
- (b) CH₃OCH₃ (liquid) > C2H5OH(l) - there is less intermolecular force in CH₃OCH₃.
- (c) Xe (gas) > (Ar(gas) - more molar mass in Xe (g)
- (d) CO₂ (gas) > CO(gas) - more molar mass in CO₂ (g)
- ( e) O₃ (gas) > O₂ - more molar mass in O₃ (g)
- ( f)N₂O₄ (gas) > NO₂(g) - more molar mass in N₂O₄ (gas)
Learn more about entropy here: https://brainly.com/question/6364271
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