A 210 Ω resistor is connected to an AC source with E0 = 14.0 V. part a
What is the peak current through the resistor if the emf frequency is 100 Hz?
part b
What is the peak current through the resistor if the emf frequency is 100 kHz?

Respuesta :

Answer:

(a) 0.0666 A (B) 0.0666 A

Explanation:

(A) We have given emf [tex]E_0=14 V[/tex]

The resistance of the circuit = 210 ohm

Emf frequency = 100 Hz there is no use of frequency in case of resistive load as it is independent on the frequency

According to ohm's law [tex]E_0=iR[/tex]

So [tex]14=i\times 210[/tex]

[tex]i=\frac{14}{210}=0.0666A[/tex]

(B) We have given emf [tex]E_0=14 V[/tex]

The resistance of the circuit = 210 ohm

Emf frequency = 100 KHz there is no use of frequency in case of resistive load as it is independent on the frequency

According to ohm's law [tex]E_0=iR[/tex]

So [tex]14=i\times 210[/tex]

[tex]i=\frac{14}{210}=0.0666A[/tex]

Note : As the resistive load is independent on the frequency so resistance will be same and so current will also be same in both case