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A 544 mg of a mixture of fluorene and benzoic acid was weighed out and subjected to an extraction and recrystallization. After this purification was completed the product crystals were dried and analyzed. The purification procedure produced 1.80 × 102 mg of fluorene and 196 mg of benzoic acid. Calculate the percent composition of this mixture.

Respuesta :

Answer: The percent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.

Explanation:

We are given:

Mass of mixture = 544 mg

Mass of fluorene after purification = [tex]1.80\times 10^2mg=180mg[/tex]

Mass of benzoic acid after purification = 196 mg

To calculate the percentage composition of a substance in a mixture, we use the equation:

[tex]\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100[/tex]

For fluorene:

[tex]\%\text{ composition of fluorene}=\frac{180}{544}\times 100=33.08\%[/tex]

Hence, the percent composition of fluorene is 33.08 %

For benzoic acid:

[tex]\%\text{ composition of benzoic acid}=\frac{196}{544}\times 100=36.03\%[/tex]

Hence, the percent composition of benzoic acid is 36.03 %

Purification is the method of extracting the substance from a sample. The percentage composition of fluorene is 33.08 %, and benzoic acid is 36.03 % in the mixture.

What are purification and crystallization?

Purification is a method of separation that involves the separation of the crystals of the substance from the mixture of the compound. While crystallization is the formation of the crystals.

Given,

  • Mass of mixture = 544 mg
  • Mass of benzoic acid after purification = 196 mg
  • Mass of fluorene after purification = 180 mg

Calculate the percentage composition of the substance in a mixture by the formula:

[tex]\rm \% \text{composition of substance} = \dfrac{\text{Mass of substance}}{\text{Mass of mixture}} \times 100[/tex]

Calculate the percentage composition of fluorine in a mixture by the formula:

[tex]\begin{aligned} \rm \%\; \text{composition of substance} &= \dfrac{\text{Mass of substance}}{\text{Mass of mixture}} \times 100\\\\&= \dfrac{180}{544} \times 100\\\\&= 33.08 \%\end{aligned}[/tex]

Calculate the percentage composition of Benzoic acid in a mixture by the formula:

[tex]\begin{aligned} \rm \%\; \text{composition of substance} &= \dfrac{\text{Mass of substance}}{\text{Mass of mixture}} \times 100\\\\&= \dfrac{196}{544} \times 100\\\\&= 36.3 \%\end{aligned}[/tex]

Therefore, the per cent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.

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