Answer:
0.7757 rev/s
Explanation:
d = Diameter of the tornado = 53 m
r = Radius of the tornado = 53/2 = 26.5 m
v = Velocity of wind = 465 km/h
Converting velocity to m/s
[tex]465=465\times \frac{1000}{3600}=\frac{775}{6}[/tex]
Angular velocity
[tex]\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{\frac{775}{6}}{26.5}\\\Rightarrow \omega=4.87\ rad/s[/tex]
[tex]\omega=4.87\frac{1}{2\pi}=0.7757\ rev/s[/tex]
∴ Angular velocity is 0.7757 rev/s
