Answer:
Explanation:
3.64 x 10⁶ J passes through 6 walls
heat energy passing through 1 wall = 0.606 x 10⁶ J
Surface Area of 1 wall A = .285² = 0.081225 m²
Temperature Difference = T₁ - T₂ = 26.8 + 94.7 = 121.5
Thickness of wall d = 3.75 x 10⁻² m
Rate of heat flow per second R = [tex]\frac{0.606 \times10^6}{24\times60\times60}[/tex]
=7.01 J per s.
Formula for rate of heat flow
R = [tex]\frac{KA(T_1-T_2)}{d}[/tex]
Where K is thermal conductivity.
7.01 = [tex]\frac{K\times121.5\times.081225}{3.75\times10^{-2}}[/tex]
K = 2.66 X 10⁻² W m⁻¹s⁻¹
