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In a survey of 1000 US adults, twenty percent say they never exercise. This is the highest level seen in five years.1 Find a confidence interval for the proportion of US adults who say they never exercise. Round your answers to three decimal places.

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Answer:

Step-by-step explanation:

Given that in a survey of 1000 US adults, twenty percent say they never exercise. This is the highest level seen in five years

p = Sample Proportion of US adults who exercise = 20%=0.20

Std error of p=[tex]\sqrt{\frac{pq}{n} } =\sqrt{\frac{0.2(1-0.2)}{1000} } \\=0.01265[/tex]

Since sample size is large we can use Z critical for 95% confidence interval

Margin of error = ±1.96(0.01265)

=0.0248

Confidence interval for proportions =p±0.0248

=[tex](0.2-00248, 0.2+0.0248)\\= (0.1752, 0.2248)[/tex]

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