Respuesta :
Answer:
Option a.
Total area of the cells to generate 6.7 kW, A = 61.4 [tex]m^{2}[/tex]
Given:
The efficiency of the cell, [tex]\eta _{cell}[/tex] = 9.1%
Power generated by the cells, P = 6.7 kW
Intensity of light, I = 1200 W/ [tex]m^{2}[/tex]
Solution:
Using the formula for intensity of light, I = [tex]\frac{P}{\eta _{cell}A}[/tex]
rearranging the above formula for Area, A:
Area, A = [tex]\frac{P}{I\eta _{cell}}[/tex]
Now, putting values in the above formula:
Area, A = [tex]\frac{6.7\times 10^{3}}{1200\times 0.091}}[/tex]
Area, A = 61.355 ≈ 61.4 [tex]m^{2}[/tex]
