Explanation:
It is given that,
Refractive index of zircon, n = 1.923
The wavelength of visible light ranging from 380 nm to 760 nm in a vacuum.
Wavelength 1, [tex]\lambda_1=380\ nm=380\times 10^{-9}\ m[/tex]
Wavelength 2, [tex]\lambda_2=760\ nm=760\times 10^{-9}\ m[/tex]
We need to find the shortest and longest wavelength. For shortest wavelength, [tex]\lambda_s=\dfrac{\lambda_1}{n}[/tex]
[tex]\lambda_s=\dfrac{380\times 10^{-9}}{1.923}=1.97\times 10^{-7}\ m[/tex]
For longest wavelength, Â [tex]\lambda_l=\dfrac{\lambda_2}{n}[/tex]
[tex]\lambda_l=\dfrac{760\times 10^{-9}}{1.923}=3.95\times 10^{-7}\ m[/tex]
Hence, this is the required solution.
