Respuesta :
Answer:
Coefficient of friction, [tex]\mu=0.535[/tex]
Explanation:
Given that,
Spring constant of the spring, k = 105 N/m
Mass of the block, m = 2 kg
The compression in the spring, x = 0.1 m
Let [tex]\mu[/tex] is the coefficient of kinetic friction between the horizontal surface and the block. The frictional force is balanced by the restoring force in the spring such that,
[tex]\mu mg=kx[/tex]
[tex]\mu=\dfrac{kx}{mg}[/tex]
[tex]\mu=\dfrac{105\ N/m\times 0.1\ m}{2\ kg\times 9.8\ m/s^2}[/tex]
[tex]\mu=0.535[/tex]
So, the coefficient of kinetic friction between the horizontal surface and the block is 0.535. Hence, this is the required solution.
The friction force is defined as the product of the coefficient of friction and normal reaction. The coefficient of kinetic friction between the horizontal surface and the block will be 0.535.
What is the friction force?
It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). Mathematically it is defined as the product of the coefficient of friction and normal reaction.
k is spring constant of the spring = 105 N/m
m is mass of the block = 2 kg
x is the compression in the spring = 0.1 m
The restoring force is balanced by the frictional in the spring
Restoring force = Friction force
[tex]\rm{kx=\mu mg}\\\\ \rm \mu= \frac{kx}{mg}\\\\ \rm \mu = 0.535[/tex]
Hence the coefficient of kinetic friction between the horizontal surface and the block will be 0.535.
To know more about friction force refer to the link;
https://brainly.com/question/1714663
