Answer:
-10.277 m/s
Explanation:
t = Time taken = 1.6 s
s = Distance travelled = 29 m
u = Initial velocity
a = Acceleration due to gravity = 9.81 m/s²
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow -29=u\times 1.6-\frac{1}{2}9.81\times 1.6^2\\\Rightarrow -29+\frac{1}{2}9.81\times 1.6^2=u1.6\\\Rightarrow -16.4432=u1.6\\\Rightarro u=\frac{-16.4432}{1.6}=-10.277\ m/s[/tex]
∴ Velocity of the object when it is 29.0 m above the ground is -10.277 m/s
