Answer:
image is 73.72 cm of right of conversing lens
image is inverted and size = 0.228 × 1.2
size of image = 0.2736 cm
Explanation:
Given data
focal length f1 = 40.0 cm
focal length f2 = 60.0 cm
tall = 1.2 cm
p = 50.0 cm
to find out
position, size, and orientation of the image
solution
we consider here diverging lens
we apply first lens formula that is
1/f = 1/q - 1/p
put here value
q = -1/50 - 1/40
q = - 22.22 cm
we know for conversing objective distance = - 300 - 22.22
conversing objective distance p2 = - 322.22 cm
for f2
q = 1/f2 + 1/p2
q = 1/60 - 1/322.22
q = 73.72 cm
image is 73.72 cm of right of conversing lens
and
so magnification
M = q / p2
M = - 73.72 / 322.22
M = - 0.228
so image is inverted and size = 0.228 × 1.2
size of image = 0.2736 cm
