A tray contains 12 ham sandwiches, 10 turkey sandwiches, and 8 peanut butter sandwiches. If Carrie takes a sandwich from the tray at random, what is the probability that she takes a ham sandwich?

Respuesta :

Answer:

[tex]\frac{2}{5}[/tex]or 0.4

Step-by-step explanation:

Number of ham sandwiches=12

Number of turkey sandwiches=10

Number of peanut butter= 8

Total number of outcomes= 12+10+8

Total number of outcomes=30

Let E be the  event of getting a ham sandwich

Favorable case to E= 12

  Probability =[tex]\frac{favourable case }{ total number of outcomes}[/tex]

P(E)= [tex]\frac{12}{30}[/tex]

P(E)=[tex]\frac{2}{5}[/tex]

P(E)=0.4

Hence , the correct answer is [tex]\frac{2}{5}[/tex] or 0.4