Body temperatures of healthy humans are distributed nearly normally with mean 98.2oF and standard deviation 0.73oF. What is the cutoff for the highest 10% of human body temperatures?

Respuesta :

Answer:

[tex]99.1[/tex]oF is the cutoff for the highest 10% of human body temperatures

Explanation:

The confidence interval for this problem is [tex]90[/tex] %

We will first evaluate the z-value for 90% confidence interval considering it one tailed.

Z from the statics table is equal to [tex]1.28\\[/tex]

Formula for z - value

[tex]z= \frac{x-u}{\alpha }[/tex]

where

x represents the required cut off value

u represents the mean value

and α represents the standard deviation

Substituting the values in above equation, we get -

[tex]1.28  = \frac{x-98.2}{0.73} \\0.9344= x-98.2\\x= 0.9344+98.2\\x=99.1\\[/tex]

Hence,

[tex]99.1[/tex]oF is the cutoff for the highest 10% of human body temperatures