Respuesta :

calculista

Answer:

[tex]11.34\frac{kg}{dm^3}[/tex]

Step-by-step explanation:

we know that

The density of lead (Pb) is [tex]11.34\frac{g}{cm^3}[/tex]

Remember that

1 kg=1,000 g ------> 1 g=1/1,000 kg

1 dm=10 cm -------> 1 cm=1/10 dm

substitute

[tex]11.34\frac{(1/1,000)}{(1/10)^3}\frac{kg}{dm^3}[/tex]

[tex]11.34\frac{(1/1,000)}{(1/1,000)}\frac{kg}{dm^3}[/tex]

Simplify

[tex]11.34\frac{kg}{dm^3}[/tex]

JeanaShupp

Answer: [tex]11.34 kg/dm^3[/tex]

Step-by-step explanation:

Given : The density of lead (Pb) is [tex]11.34 g/cm^3[/tex]

We know that 1 kg = 1000 gm

⇒ 1 gm =[tex]\dfrac{1}{1000}\ kg[/tex]

1 dm = 10 cm

Also, 1 cm = [tex]\dfrac{1}{10}\ dm[/tex]

Then the density of Pb =[tex]11.34\times\dfrac{10\times10\times10}{1000}[/tex]

Then the density of Pb =[tex]11.34 kg/dm^3[/tex]

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