Answer:
The wavelength of light is 533 nm.
Explanation:
It is given that,
Width of a single slit, [tex]d=4.05\times 10^{-6}\ m[/tex]
Light has its third minimum at an angle of 23.3° when it falls on a single slit. For destructive interference, the equation for minima is given by:
[tex]d\ sin\theta=n\lambda[/tex]
Here, n = 3
[tex]\lambda=\dfrac{d\ sin\theta}{n}[/tex]
[tex]\lambda=\dfrac{4.05\times 10^{-6}\times sin(23.3)}{3}[/tex]
[tex]\lambda=5.33\times 10^{-7}\ m[/tex]
[tex]\lambda=533\ nm[/tex]
So, the wavelength of the light is 533 nm. Hence, this is the required solution.
