Consider a 200 g sample of U-238 with decay constant 2.951x10^-16 min^1. Approximately how many disintegrations will occur per minute?

Respuesta :

Answer:

The disintegrations is [tex]5.902\times10^{-17}\ decay /min[/tex].

Explanation:

Given that,

Weight of sample = 200 g

Decay constant [tex]\lambda=2.951\times10^{-16}\ min^{-1}[/tex]

We need to calculate the disintegrations

Using formula of disintegrations

[tex]\dfrac{dN}{dt}=\lambda N[/tex]

Where, [tex]\lambda[/tex] = decay constant

N = number of atoms present at time t

Put the value into the formula

[tex]\dfrac{dN}{dt}=2.951\times10^{-16}\times200\times10^{-3}[/tex]

[tex]\dfrac{dN}{dt}=5.902\times10^{-17}\ decay /min[/tex]

Hence, The disintegrations is [tex]5.902\times10^{-17}\ decay /min[/tex].