jacobvalero197 jacobvalero197

23-08-2019
Mathematics

contestada

Factor x2 + 9 in the complex numbers.
A) (x + 3)(x - 3)
B) (x + 3)(x + 3)
C) (x + 3i)(x - 3i)
D) (x + 3i)(x + 3i)

Respuesta :

aamaruf aamaruf

23-08-2019

Answer:

C) (x + 3i)(x - 3i)

Step-by-step explanation:

(x + 3i)(x - 3i)

=x² - (3i)² [(a+b)(a-b)=a²-b²]

=x² - 9i²

=x² - 9(-1) [i²=-1]

= x² + 9

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profarouk profarouk

23-08-2019

Good evening ,

______

Answer:

The right answer is C

_________________

Step-by-step explanation:

x² + 9 = x² − (−9) = x² − (i²×9) = x² − i²× 3² = x² − (3i)² = (x + 3i)(x - 3i).

:)

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