A battery, an inductor, a resistor, and a switch are wired in series. The battery produces an emf of 12.0 V and the inductor is rated at 25.0 mH. What size resistor should be used to yield 65% of the maximum current through the inductor when the switch has been closed for 0.35 s?

Respuesta :

Answer:

0.075 ohm

Explanation:

[tex]i_{o}[/tex] = maximum value of the current

[tex]i[/tex] = value of the current after time "t = 0.35 s" = 0.65 [tex]i_{o}[/tex]

[tex]R[/tex]  = resistance of the resistor = ?

[tex]L[/tex]  = Inductance of the inductor = 25 mH = 0.025 H

[tex]T[/tex] = Time constant of the circuit

Current at any time is given as

[tex]i = i_{o}(1 - e^{\frac{-t}{T}})[/tex]

[tex](0.65) i_{o} = i_{o}(1 - e^{\frac{-0.35}{T}})[/tex]

[tex](0.65) = (1 - e^{\frac{-0.35}{T}})[/tex]

[tex]T = 0.333[/tex] sec

Time constant is given as

[tex]T = \frac{L}{R}[/tex]

[tex]0.333 = \frac{0.025}{R}[/tex]

[tex]R = 0.075 [/tex] ohm