Answer: [tex]0.0000000000667 N \frac{kg^{2}}{m^{2}}[/tex]
Explanation:
According to the Universal Law of Gravitation:
The force [tex]F[/tex] exerted between two bodies of masses [tex]m1[/tex] and [tex]m2[/tex] and separated by a distance [tex]r[/tex] is equal to the product of their masses and inversely proportional to the square of the distance.
Written in a mathematicall form is:
[tex]F=G\frac{(m1)(m2)}{r^2}[/tex]
If we rewrite this formula:
[tex]G=\frac{Fr^2}{(m1)(m2)}[/tex]
Where [tex]G=6.67(10)^{-11}N \frac{kg^{2}}{m^{2}}[/tex] is the gravitational constant, which in standard notation is:
[tex]0.0000000000667 N \frac{kg^{2}}{m^{2}}[/tex]
Answer:
[tex]G=6.67\times 10^{-11}\ Nkg^2/m^2=0.0000000000667\ Nkg^2/m^2[/tex]
Explanation:
The attractive force acting between any tow masses is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]
G is the universal gravitational constant
The value of G is, [tex]G=6.67\times 10^{-11}\ Nkg^2/m^2[/tex]
We need to write the value of G in standard notation. A number is written in scientific notation as :
[tex]N=a\times 10^b[/tex]
The given value of G is in scientific notation. Its standard notation is given by :
[tex]G=6.67\times 10^{-11}\ Nkg^2/m^2=0.0000000000667\ Nkg^2/m^2[/tex]
So, the correct option is (d). Hence, this is the required solution.
