Respuesta :
Answer:
distance, x = 38.17 m
Given:
velocity of the football, v = 20.5 m/s
football projected at an angle, [tex]\theta = 30^{\circ}[/tex]
Period of flight, T = 2.15 s
Solution:
Since, the velocity is projected at some angle, so it can be resolved in horizontal and vertical components:
vertical component, [tex]u_{v} = usin\theta [/tex]
horizontal component, [tex]u_{h} = ucos\theta [/tex]
the component responsible to cover certain distance is [tex]u_{h} = ucos\theta[/tex]
Therefore, the distance covered by the football, x is given by:
[tex]x = ucos\theta \times T[/tex]
⇒ [tex]x = 20.5cos30^{\circ}\times 2.15[/tex]
x = 38.17 m
