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An electric motor has an effective resistance of 22 22 and an inductive reactance of 72 12 when working under load. The voltage amplitude across the alternating source is 420V. Calculate the current amplitude. in A.

Respuesta :

Answer:

Current amplitude, I = 5.57 A

Explanation:

It is given that,

Effective resistance, R = 22 ohms

Inductive reactance, L = 72 ohms

Voltage of the alternating source, V = 420 volt

The total impedance of the RL circuit is given by :

[tex]Z=\sqrt{R^2+L^2}[/tex]

[tex]Z=\sqrt{(22)^2+(72)^2}[/tex]

Z = 75.28 ohms

From Ohm's law,

[tex]V=I\times Z[/tex]

[tex]I=\dfrac{V}{Z}[/tex]

[tex]I=\dfrac{420}{75.28}[/tex]

I = 5.57 A

So, the current amplitude of the electric motor is 5.57 A. Hence, this is the required solution.

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