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A single-wavelength beam of light is pointed at a dark shield with two narrow slits. As a result, an interference pattern forms in the space on the other side of the partition. The wavelength is 635 nm, and the first-order bright fringe lies at a 16.6° angle from the central maximum. What is the slit separation (in µm)?

Respuesta :

Answer:

The slit separation is 2.2μm.

Explanation:

Given that,

Wavelength = 635 nm

Angle = 16.6°

Order number = 1

We need to calculate the slit position

Using formula of slit distance

[tex]d\sin\theta= m\lambda[/tex]

[tex]d=\dfrac{m\lambda}{\sin\theta}[/tex]

Where, [tex]\lambda[/tex] = wavelength

m = order number

Put the value into the formula

[tex]d=\dfrac{1\times635\times10^{-9}}{\sin 16.6}[/tex]

[tex]d=2.2\times10^{-6}\ m[/tex]

[tex]d=2.2\ \mu m[/tex]

Hence, The slit separation is 2.2μm.

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