Answer:
1.693 feet
Explanation:
We have given the pipe deliver 90 gpm
We know that 1 cubic feet per second =448.833 gpm
So 90 gpm will be equal to [tex]\frac{90}{448.833}=0.2\frac{feet^3}{sec}[/tex]
If d is the diameter of the pipe then [tex]V_{avg}=\frac{Q}{A}=\frac{0.2}{\frac{\pi }{4}d^2}=\frac{0.255}{d^2}[/tex]
For the pipe flow critical Reynolds number =2300
We have given [tex]\nu =6.55\times 10^{-5}ft^2/sec[/tex]
So [tex]\frac{V_{avg}\times d}{\nu }=2300[/tex]
[tex]\frac{0.255\times d}{d^2\times 6.55\times 10^{-5}}=2300[/tex]
d=1.693 feet
