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A taxidermist prepares a specimen using a 15A oven plugged into a 220V outlet to evaporate the water from the body. A specimen is properly cured when the water in the bodily fluids and tissues is removed; if 20.% of a 15kg specimen is water, calculate the time required for the specimen to lose 20.0% of its weight in water. For simplicity, assume the specimen is at 100.0°C when placed in the oven so that all the heat is used only to evaporate the water; the latent heat of vaporization is 2.26X1010 J/kg. A. 55min B. 34min C. 20min OD. 16 min E. 12min

Respuesta :

Answer:

B) 34 min.

Explanation:

Power of oven = volt x current = 220 x 15 = 3300 Js⁻¹

Heat required to vaporize 20% of 15 kg

= mass of water x latent heat of vaporization

= 15 x .2 x 2.26 x 10⁶ = 6.78 x 10⁶

Time taken by oven to provide this heat

= heat energy / power

=[tex]\frac{6.78\times 10^{6}}{3300}[/tex]

=34 min

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