contestada

A new neighborhood activity complex is being built in erie. The perimeter of the rectangular playing field is 256 yards. The length of the field is 4 yards less than double the width. What are the dimensions of the playing field?

Respuesta :

calculista

Answer:

The length of the rectangular playing field is 84 yards and the width is 44 yards

Step-by-step explanation:

Let

x ------> the length of the rectangular playing field

y -----> the width of the rectangular playing field

we know that

The perimeter of the rectangular playing field is equal to

[tex]P=2(x+y)[/tex]

[tex]P=256\ yd[/tex]

so

[tex]256=2(x+y)[/tex] ------> equation A

we have that

[tex]x=2y-4[/tex] -----> equation B

Solve the system by substitution

Substitute equation B in equation A and solve for y

[tex]256=2(2y-4+y)[/tex]

[tex]128=3y-4[/tex]

[tex]3y=128+4[/tex]

[tex]3y=132[/tex]

[tex]y=44[/tex]

Find the value of x

[tex]x=2(44)-4=84[/tex]

therefore

The length of the rectangular playing field is 84 yards and the width is 44 yards

Otras preguntas