Respuesta :
Answer:
The final image relative to the converging lens is 34 cm.
Explanation:
Given that,
Focal length of diverging lens = -12.0 cm
Focal length of converging lens = 34.0 cm
Height of object = 2.0 cm
Distance of object = 12 cm
Because object at focal point
We need to calculate the image distance of diverging lens
Using formula of lens
[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{-12}-\dfrac{1}{-12}[/tex]
[tex]v=\infty[/tex]
The rays are parallel to the principle axis after passing from the diverging lens.
We need to calculate the image distance of converging lens
Now, object distance is ∞
Using formula of lens
[tex]\dfrac{1}{v}=\dfrac{1}{34}-\dfrac{1}{\infty}[/tex]
[tex]v=34[/tex]
The image distance is 34 cm right to the converging lens.
Hence, The final image relative to the converging lens is 34 cm.
