Explanation:
It is given that,
Length of microscope, l = 17 cm = 0.17 m
Magnification of objective lens, m₀ = -50
Magnification of eyepiece, [tex]m_e=20[/tex]
(a) Magnification in terms of length is given by :
[tex]m_o=-\dfrac{l}{f_o}[/tex]
[tex]f_o=-\dfrac{l}{m}[/tex]
[tex]f_o=-\dfrac{0.17}{-50}[/tex]
[tex]f_o=0.0034\ m[/tex]
[tex]f_o=3.4\ mm[/tex]
(b) Focal length of eyepiece is given by :
[tex]m_e=\dfrac{25}{f_e}[/tex]
[tex]f_e=\dfrac{25}{m_e}[/tex]
[tex]f_e=\dfrac{25}{20}[/tex]
[tex]f_e=1.25\ m[/tex]
(c) Total magnification of the microscope,
[tex]M=m_o\times m_e[/tex]
[tex]M=-50\times 20[/tex]
M = -100
Hence, this is the required solution.
