Respuesta :
Answer:
So the exit velocity of water is 4.5 m/s
Explanation:
Given that
Water entering pressure = 1.5 MPa
Temperature = 150°C
Velocity = 4.5 m/s
From first law of thermodynamics for open system
[tex]h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+W[/tex]
Here given that valve is adiabatic so Q= 0
In valve W= 0
Wen also also know that throttling process is an constant enthaply process so
[tex]h_1=h_2[/tex]
[tex]h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+W[/tex]
[tex]h_1+\dfrac{V_1^2}{2}+0=h_1+\dfrac{V_2^2}{2}+0[/tex]
So from above equation we can say that
[tex]V_2=V_1[/tex]
So the exit velocity of water is 4.5 m/s
