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A 1.50 cm high diamond ring is placed 20.0 cm from a concave mirror with radius of curvature 30.00 cm. The magnification is _____.

Respuesta :

Answer:

Magnification, m = -0.42

Explanation:

It is given that,

Height of diamond ring, h = 1.5 cm

Object distance, u = -20 cm

Radius of curvature of concave mirror, R = 30 cm

Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)

Using mirror's formula :

[tex]\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}[/tex], f = focal length of the mirror

[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}[/tex]

[tex]\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}[/tex]

v = -8.57 cm

The magnification of a mirror is given by,

[tex]m=\dfrac{-v}{u}[/tex]

[tex]m=\dfrac{-(-8.57)}{-20}[/tex]

m = -0.42

So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.