An object is placed 4 cm in front of a +2 cm focal length lens. If a second identical lens is now placed 8cm behind the first, where will the final image be located? a) 2 cm behind the second lens b) 4 cm behind the first lens c) 10 cm in front of the first lens. d) -5 cm from the second lens.

Respuesta :

Answer:

The final image be located 2 cm behind the second lens.

(a) is correct option.

Explanation:

Given that,

Focal length = +2 cm,

Object distance = 4 cm

If a second identical lens is now placed 8 cm behind the first

We need to calculate the image distance

Using formula of focal length

[tex]\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}[/tex]

Put the value into the formula

[tex]\dfrac{1}{2}=\dfrac{1}{v}+\dfrac{1}{-4}[/tex]

[tex]\dfrac{1}{v}=\dfrac{1}{2}+\dfrac{1}{4}[/tex]

[tex]\dfrac{1}{v}=\dfrac{3}{4}[/tex]

[tex]v=1.333\ cm[/tex]

Where two lens are separated by 8 cm

The image of first lens become object for second lens

Then object distance is

[tex]u = 8 -1.33= 6.67 cm[/tex]

Where two lens are same means have same focal length then image distance is

Using formula of lenses

[tex]\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}[/tex]

Put the value into the formula

[tex]\dfrac{1}{2}=\dfrac{1}{v}+\dfrac{1}{-6.67}[/tex]

[tex]\dfrac{1}{v}=\dfrac{1}{2}+\dfrac{1}{6.67}[/tex]

[tex]v=1.54\ cm[/tex]

Round off value of v is 2 cm

Hence, The final image be located 2 cm behind the second lens.