For this case we have that the equation of a line of the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We found the slope:
[tex](x1, y1) :( 0,2)\\(x2, y2) :( 4,1)\\m = \frac {y2-y1} {x2-x1} = \frac {1-2} {4-0} = \frac {-1} {4} = - \frac {1} {4}[/tex]
Thus, the equation is of the form:
[tex]y = - \frac {1} {4} x + b[/tex]
We find b, substituting any of the points:
[tex]2 = - \frac {1} {4} (0) + b\\b = 2[/tex]
Finally, the equation is:
[tex]y = - \frac {1} {4} x + 2[/tex]
ANswer:
[tex]y = - \frac {1} {4} x + 2[/tex]
