Respuesta :
Answer: The empirical formula will be [tex]SF_6[/tex]
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of S= 3.21 g
Mass of F = 11.4 g
Step 1 : convert given masses into moles.
Moles of S =[tex]\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{3.21g}{32g/mole}=0.1moles[/tex]
Moles of F =[tex]\frac{\text{ given mass of F}{\text{ molar mass of F}}= \frac{11.04g}{19g/mole}=0.6moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For S= [tex]\frac{0.1}{0.1}=1[/tex]
For F = [tex]\frac{0.6}{0.1}=6[/tex]
The ratio of S: F= 1: 6
Hence the empirical formula is [tex]SF_6[/tex]
