Answer:
2[tex]\sqrt{2}[/tex]
Step-by-step explanation:
let the other leg be x
Using Pythagoras' identity
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 1² = 3²
x² + 1 = 9 ( subtract 1 from both sides )
x² = 8 ( take the square root of both sides )
x = [tex]\sqrt{8}[/tex]
= [tex]\sqrt{4(2)}[/tex]
= [tex]\sqrt{4}[/tex] × [tex]\sqrt{2}[/tex] = 2[tex]\sqrt{2}[/tex] ← exact value
