Answer:
[tex]\large\boxed{t>-4\to t\in(-4,\ \infty)}[/tex]
Step-by-step explanation:
We need to convert the inequality to the form t > some number
or t < some number.
[tex]2>-3t-10\qquad\text{subtract 2 from both sides}\\\\2-2>-3t-10-2\\\\0>-3t-12\qquad\text{add}\ 3t\ \text{to both sides}\\\\0+3t>-3t+3t-12\\\\3t>-12\qquad\text{divide both sides by 3}\\\\\dfrac{3t}{3}>\dfrac{-12}{3}\\\\t>-4[/tex]
If you want to draw a solution on a numeric line.
for <,> - open circle (the number is not in the set of solutions)
for ≤, ≥ - closed circle (the number is in the set of solutions)
for <, ≤ - draw a line to the left
for>, ≥ - draw a line to the right.
We have t > -4
open circle, a line to the right (look at the picture).
If you want the solution in an interval, then
[tex]t\in(-4, \infty)[/tex]
