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What are the discontinuity and zero of the function f(x) = quantity x squared plus 5 x plus 4 end quantity over quantity x plus 4?
Discontinuity at (āˆ’4, āˆ’3), zero at (āˆ’1, 0)
Discontinuity at (āˆ’4, āˆ’3), zero at (1, 0)
Discontinuity at (4, 3), zero at (āˆ’1, 0)
Discontinuity at (4, 3), zero at (1, 0)

Respuesta :

sqdancefan

Answer:

Ā  Discontinuity at (āˆ’4, āˆ’3), zero at (āˆ’1, 0)

Step-by-step explanation:

The expression simplifies to ...

Ā  [tex]\dfrac{x^2+5x+4}{x+4}=\dfrac{(x+4)(x+1)}{(x+4)}=x+1 \qquad\text{$x\ne -4$}[/tex]

This is undefined at x=-4, hence there is a discontinuity there, and is zero for x=-1.

There is a discontinuity at x=-4, and a zero at (-1, 0).

Ver imagen sqdancefan

Answer:

Discontinuity at (āˆ’4, āˆ’3), zero at (āˆ’1, 0)

Step-by-step explanation:

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