Answer:17.15 m/s
Explanation:
angle of inclination[tex](\theta )=30^{\circ}[/tex]
height=15 m
mass of block=2 kg
Conserving energy at top and bottom
energy at top of inclined plane([tex]E_1[/tex])=mgh
[tex]E_1=2\times 9.81\times 15=294.3 J[/tex]
energy at bottom[tex](E_2)=\frac{mv^2}{2}[/tex]
[tex]E_2=\frac{2\times v^2}{2}[/tex]
[tex]E_1=E_2[/tex]
[tex]294.3=\frac{2\times v^2}{2}[/tex]
[tex]v=\sqrt{\frac{2\times 294.3}{2}}[/tex]
v=17.15 m/s
