Respuesta :
Answer:
(a) 8.2 x 10^-8 N
(b) 3.6 x 10^-47 N , 2.27 x 10^39
Explanation:
charge of proton, q1 = 1.6 x 10^-19 C
charge of electron, q2 = - 1.6 x 10^-19 C
radius of orbit, r = 0.053 nm = 0.053 x 10^-9 m
mass of electron, me = 9.1 x 10^-31 kg
mass of proton, mp = 1.67 x 10^-27 kg
Gravitational constant, G = 6.67 x 10^-11 Nm^2/kg^2
(a) The electrostatic force between two charges is given by
[tex]F_{e}=\frac{Kq_{1}q_{2}}{r^2}[/tex]
Where, K is the coulombic constant = 9 x 10^9 Nm^2/C^2
By substituting the values
[tex]F_{e}=\frac{9\times 10^{9}\times 1.6\times 10^{-19}\1.6\times 10^{-19}}{\left ( 0.053 \times 10^{-9} \right )^2}[/tex]
Fe = 8.2 x 10^-8 N
(b) The gravitational force between the electron and proton is given by
[tex]F_{g}=\frac{Gm_{e}m_{p}}{r^{2}}[/tex]
[tex]F_{g}=\frac{6.67\times 10^{-11}\times 9.1\times 10^{-31}\1.67\times 10^{-27}}{\left ( 0.053 \times 10^{-9} \right )^2}[/tex]
Fg = 3.6 x 10^-47 N
[tex]\frac{F_{e}}{F_{g}}=\frac{8.2\times10^{-8}}{3.6\times 10^{-47}}[/tex]
[tex]\frac{F_{e}}{F_{g}}=2.27\times 10^{39}[/tex]
